0=3b^2+7b-6

Solution for 0=3b^2+7b-6 equation:

0=3b^2+7b-6

We move all terms to the left:

0-(3b^2+7b-6)=0

We add all the numbers together, and all the variables

-(3b^2+7b-6)=0

We get rid of parentheses

-3b^2-7b+6=0

a = -3; b = -7; c = +6;
Δ = b2-4ac
Δ = -72-4·(-3)·6
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-11}{2*-3}=\frac{-4}{-6}
=2/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+11}{2*-3}=\frac{18}{-6}
=-3
$